What are the solutions to the equation x^2-16x+89=0 ?

The solutions to the equation x^2-16x+89=0 are x=8+5i,x=8-5i

Find the zeros of x^2-16x+89=0

The zeros of x^2-16x+89=0 are x=8+5i,x=8-5i

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x^{2} - 16 x + 89 = 0

x = 8 + 5 i, x = 8 - 5 i

Solution steps

x^{2} - 16 x + 89 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 89}{2 \cdot 1}

Simplify

(- 16)^{2} - 4 \cdot 1 \cdot 89 : 10 i

x_{1, 2} = \frac{- ( - 16 ) \pm 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 10 i}{2 \cdot 1}

x = \frac{- ( - 16 ) + 10 i}{2 \cdot 1} : 8 + 5 i

x = \frac{- ( - 16 ) - 10 i}{2 \cdot 1} : 8 - 5 i

The solutions to the quadratic equation are:

x = 8 + 5 i, x = 8 - 5 i

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7 x - 3 = 9 x + 5

6 x^{2} + 7 x - 49

What are the solutions to the equation x^2-16x+89=0 ?
The solutions to the equation x^2-16x+89=0 are x=8+5i,x=8-5i
Find the zeros of x^2-16x+89=0
The zeros of x^2-16x+89=0 are x=8+5i,x=8-5i