What is factor x^8+x^4y^4+y^8 ?

The solution to factor x^8+x^4y^4+y^8 is (x^4+y^4+x^2y^2)(x^4+y^4-x^2y^2)

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factor x^8+x^4y^4+y^8

factor

x^{8} + x^{4} y^{4} + y^{8}

(x^{4} + y^{4} + x^{2} y^{2}) (x^{4} + y^{4} - x^{2} y^{2})

Solution steps

x^{8} + x^{4} y^{4} + y^{8}

Add and subtract

x^{4} y^{4}

= x^{8} + 2 x^{4} y^{4} + y^{8} - x^{4} y^{4}

Factor

x^{8} + 2 x^{4} y^{4} + y^{8} : (x^{4} + y^{4})^{2}

= (x^{4} + y^{4})^{2} - x^{4} y^{4}

Apply exponent rules

= (x^{4} + y^{4})^{2} - (x^{2} y^{2})^{2}

Factor

(x^{4} + y^{4})^{2} - (x^{2} y^{2})^{2} : (x^{4} + y^{4} + x^{2} y^{2}) (x^{4} + y^{4} - x^{2} y^{2})

= (x^{4} + y^{4} + x^{2} y^{2}) (x^{4} + y^{4} - x^{2} y^{2})

(- 6.7 + 2 z) (- 1.5)

\frac{( x - 1 )}{( x ^{2} - 1 )}

(- y^{2} - 1)^{3}

2 x^{3} - 6 x^{2} + 6 x - 2

(1 - h)^{3}

What is factor x^8+x^4y^4+y^8 ?
The solution to factor x^8+x^4y^4+y^8 is (x^4+y^4+x^2y^2)(x^4+y^4-x^2y^2)