What is factor 8y^3+12y^2+6y+1 ?

The solution to factor 8y^3+12y^2+6y+1 is (2y+1)^3

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factor 8y^3+12y^2+6y+1

factor

8 y^{3} + 12 y^{2} + 6 y + 1

(2 y + 1)^{3}

Solution steps

8 y^{3} + 12 y^{2} + 6 y + 1

Use the rational root theorem

= (2 y + 1) \frac{8 y ^{3} + 12 y ^{2} + 6 y + 1}{2 y + 1}

\frac{8 y ^{3} + 12 y ^{2} + 6 y + 1}{2 y + 1} = 4 y^{2} + 4 y + 1

= (2 y + 1) (4 y^{2} + 4 y + 1)

Factor

4 y^{2} + 4 y + 1 : (2 y + 1) (2 y + 1)

= (2 y + 1) (2 y + 1) (2 y + 1)

Apply exponent rule:

aaa = a^{3}

(2 y + 1) (2 y + 1) (2 y + 1) = (2 y + 1)^{3}

= (2 y + 1)^{3}

\frac{0.7 x ^{3} + 0.7 x ^{3} - 5}{9 x ^{3}}

x^{5} + x^{4} - x^{2} - x

(2 x)^{3} + (3 y)^{3} + (4 z)^{3} - 3 (2 x) (3 y) (4 z)

6 x^{3} + 13 x^{2} + x - 2

x^{18} - y^{18}

What is factor 8y^3+12y^2+6y+1 ?
The solution to factor 8y^3+12y^2+6y+1 is (2y+1)^3