What is expand (2^{x+1}+3)^2 ?

The solution to expand (2^{x+1}+3)^2 is 4^{x+1}+6*2^{x+1}+9

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expand (2^{x+1}+3)^2

expand

(2^{x + 1} + 3)^{2}

4^{x + 1} + 6 \cdot 2^{x + 1} + 9

Solution steps

(2^{x + 1} + 3)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(2^{x + 1} + 3)^{2} = (2^{x + 1})^{2} + 2 \cdot 2^{x + 1} \cdot 3 + 3^{2}

= (2^{x + 1})^{2} + 2 \cdot 2^{x + 1} \cdot 3 + 3^{2}

Simplify

(2^{x + 1})^{2} + 2 \cdot 2^{x + 1} \cdot 3 + 3^{2} : 4^{x + 1} + 6 \cdot 2^{x + 1} + 9

= 4^{x + 1} + 6 \cdot 2^{x + 1} + 9

sin^{3} (x) + sin^{2} (x) - sin (x)

(3 a - 7 b - c)^{2}

\frac{s}{s ( s ^{2} + 4 ) ^{2}}

- 3 (a - 4 b)

(2 x + 5)^{3} + (5 x - 9)^{3}

What is expand (2^{x+1}+3)^2 ?
The solution to expand (2^{x+1}+3)^2 is 4^{x+1}+6*2^{x+1}+9