What is 1+2 b/3+(b^2)/9 ?

The solution to 1+2 b/3+(b^2)/9 is 1+(2b)/3+(b^2)/9

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simplify 1+2 b/3+(b^2)/9

simplify

1 + 2 \frac{b}{3} + \frac{b ^{2}}{9}

1 + \frac{2 b}{3} + \frac{b ^{2}}{9}

Solution steps

1 + 2 \cdot \frac{b}{3} + \frac{b ^{2}}{9}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

2 \cdot \frac{b}{3} = \frac{2 b}{3}

= 1 + \frac{2 b}{3} + \frac{b ^{2}}{9}

(\frac{x}{4 - 2 y})^{3}

w^{3} - 6 w - 9

(x + y)^{3} - x^{3} - y^{3}

f \frac{( x )}{x ^{3}} + 2 x^{2} + 1

\frac{( b ^{2} - 5 b )}{( 3 b - 4 a )} \cdot \frac{( 9 b ^{2} - 16 a ^{2} )}{( b ^{2} - 25 )}