What is 1/(2xy^2(2/3 xy-3)) ?

The solution to 1/(2xy^2(2/3 xy-3)) is 3/(2xy^2(2xy-9))

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simplify 1/(2xy^2(2/3 xy-3))

simplify

\frac{1}{2 x y ^{2} ( \frac{2}{3} x y - 3 )}

\frac{3}{2 x y ^{2} ( 2 x y - 9 )}

Solution steps

\frac{1}{2 x y ^{2} ( \frac{2}{3} x y - 3 )}

Multiply

\frac{2}{3} x y : \frac{2 x y}{3}

= \frac{1}{2 x y ^{2} ( \frac{2 x y}{3} - 3 )}

Join

\frac{2 x y}{3} - 3 : \frac{2 x y - 9}{3}

= \frac{1}{2 \cdot \frac{2 x y - 9}{3} x y ^{2}}

Multiply

2 x y^{2} \frac{2 x y - 9}{3} : \frac{2 x y ^{2} ( 2 x y - 9 )}{3}

= \frac{1}{\frac{2 x y ^{2} ( 2 x y - 9 )}{3}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{3}{( 2 x y - 9 ) \cdot 2 x y ^{2}}

\frac{1}{2} x + \frac{1}{x}

\frac{t ^{n - 1}}{( 1 - e ^{- t} )}

2 x - 1 + 6 x y - 3 y

a \cdot 2.64 d^{3} + 216 a^{3}

36 x^{2} - 9 y^{2}

What is 1/(2xy^2(2/3 xy-3)) ?
The solution to 1/(2xy^2(2/3 xy-3)) is 3/(2xy^2(2xy-9))