What is factor m^3+3m^2*n+3m*n^2+n^3 ?

The solution to factor m^3+3m^2*n+3m*n^2+n^3 is (m+n)^3

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factor m^3+3m^2n+3mn^2+n^3

factor

m^{3} + 3 m^{2} \cdot n + 3 m \cdot n^{2} + n^{3}

(m + n)^{3}

Solution steps

m^{3} + 3 m^{2} n + 3 m n^{2} + n^{3}

Apply cube of sum rule:

x^{3} + 3 x^{2} y + 3 x y^{2} + y^{3} = (x + y)^{3}

m^{3} + 3 m^{2} n + 3 m n^{2} + n^{3} = (m + n)^{3}

= (m + n)^{3}

(sin^{2} (a) - 1) (1 + tan^{2} (a))

- 3 sin^{2} (a) - 6 - 3 cos^{2} (a)

3 x + 52 x + 3

9 b^{2} - 4 a^{2} + 20 a - 25

x^{10} - (1 0^{x})^{6} + 9 x

What is factor m^3+3m^2*n+3m*n^2+n^3 ?
The solution to factor m^3+3m^2*n+3m*n^2+n^3 is (m+n)^3