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Popular >

simplify 4/(3x^{n+1)*x^2xy}

Solution

simplify

\frac{4}{3 x ^{n + 1} \cdot x ^{2} x y}

Solution

\frac{4}{3 x ^{n + 4} y}

Solution steps

\frac{4}{3 x ^{n + 1} x ^{2} x y}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{n + 1} x^{2} x = x^{n + 1 + 2 + 1}

= \frac{4}{3 x ^{n + 1 + 2 + 1} y}

Add the numbers:

1 + 2 + 1 = 4

= \frac{4}{3 x ^{n + 4} y}

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Frequently Asked Questions (FAQ)

What is 4/(3x^{n+1)*x^2xy} ?
The solution to 4/(3x^{n+1)*x^2xy} is 4/(3x^{n+4)y}