What is (((n-l)!(n-2)!))/(((n!)^2)) ?

The solution to (((n-l)!(n-2)!))/(((n!)^2)) is ((n-l)!)/((n-1)nn!)

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simplify (((n-l)!(n-2)!))/(((n!)^2))

simplify

\frac{( ( n - l ) ! ( n - 2 ) ! )}{( ( n ! ) ^{2} )}

\frac{( n - l ) !}{( n - 1 ) nn !}

Solution steps

\frac{( n - l ) ! ( n - 2 ) !}{n ! ^{2}}

Apply exponent rule:

a^{2} = aa

n!^{2} = n! n!

= \frac{( n - l ) ! ( n - 2 ) !}{n ! n !}

Cancel the factorials:

\frac{n !}{( n + m ) !} = \frac{1}{( n + 1 ) \cdot ( n + 2 ) \dots ( n + m )}

\frac{( n - 2 ) !}{n !} = \frac{1}{( n - 1 ) n}

= \frac{( n - l ) !}{( n - 1 ) nn !}

x^{2} - (a + a^{1}) x + 1

f (x) 2 x^{3} - 5 x^{2} + 3 x - 15

(2 x - y + 5 z - 15)^{2}

(\frac{1}{4 x + 2 y})^{3}

2^{x} + 2^{- x}

What is (((n-l)!(n-2)!))/(((n!)^2)) ?
The solution to (((n-l)!(n-2)!))/(((n!)^2)) is ((n-l)!)/((n-1)nn!)