What are the solutions to the equation 12x^2-160x+400=0 ?

The solutions to the equation 12x^2-160x+400=0 are x=10,x= 10/3

Find the zeros of 12x^2-160x+400=0

The zeros of 12x^2-160x+400=0 are x=10,x= 10/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} - 160 x + 400 = 0

x = 10, x = \frac{10}{3}

Decimal Notation

x = 10, x = 3.33333 \dots

Solution steps

12 x^{2} - 160 x + 400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 160 ) \pm ( - 160 ) ^{2} - 4 \cdot 12 \cdot 400}{2 \cdot 12}

(- 160)^{2} - 4 \cdot 12 \cdot 400 = 80

x_{1, 2} = \frac{- ( - 160 ) \pm 80}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 160 ) + 80}{2 \cdot 12}, x_{2} = \frac{- ( - 160 ) - 80}{2 \cdot 12}

x = \frac{- ( - 160 ) + 80}{2 \cdot 12} : 10

x = \frac{- ( - 160 ) - 80}{2 \cdot 12} : \frac{10}{3}

The solutions to the quadratic equation are:

x = 10, x = \frac{10}{3}

4 ∣ 4 - 3 x ∣ = 4 x + 6

- \frac{4}{i}

- 5 < x < 2

x + 5 = 12

27 \cdot 2

What are the solutions to the equation 12x^2-160x+400=0 ?
The solutions to the equation 12x^2-160x+400=0 are x=10,x= 10/3
Find the zeros of 12x^2-160x+400=0
The zeros of 12x^2-160x+400=0 are x=10,x= 10/3