What is 1/((1+sqrt(2))^+1v^2+(v^3)^+1v^3+v^4) ?

The solution to 1/((1+sqrt(2))^+1v^2+(v^3)^+1v^3+v^4) is 1/((1+sqrt(2))^{)v^2+v^6+v^4}

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simplify 1/((1+sqrt(2))^+1v^2+(v^3)^+1v^3+v^4)

simplify

\frac{1}{( 1 + 2 ) ^{+} 1 v ^{2} + ( v ^{3} ) ^{+} 1 v ^{3} + v ^{4}}

\frac{1}{( 1 + 2 ) v ^{2} + v ^{6} + v ^{4}}

Solution steps

\frac{1}{( 1 + 2 ) ^{+} \cdot 1 \cdot v ^{2} + ( v ^{3} ) ^{+} \cdot 1 \cdot v ^{3} + v ^{4}}

(1 + 2)^{+} \cdot 1 \cdot v^{2} + (v^{3})^{+} \cdot 1 \cdot v^{3} + v^{4} = (1 + 2)^{+} v^{2} + v^{3} (v^{3})^{+} + v^{4}

= \frac{1}{( 1 + 2 ) v ^{2} + v ^{3} ( v ^{3} ) + v ^{4}}

(v^{3})^{+} v^{3} = v^{6}

= \frac{1}{( 1 + 2 ) v ^{2} + v ^{6} + v ^{4}}

a^{4} + 2 a^{3} + 1

(2^{x})^{x}

lo g_{10} (0.5) (2 - x) - 1

15 c^{8} - 15 c^{7}

2 (2 x^{3} - 1)^{3} - 1

What is 1/((1+sqrt(2))^+1v^2+(v^3)^+1v^3+v^4) ?
The solution to 1/((1+sqrt(2))^+1v^2+(v^3)^+1v^3+v^4) is 1/((1+sqrt(2))^{)v^2+v^6+v^4}