What is (c^2d^3y^{-4})^0(2c^3d^{-2}y^3) ?

The solution to (c^2d^3y^{-4})^0(2c^3d^{-2}y^3) is (2c^3y^3)/(d^2)

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simplify (c^2d^3y^{-4})^0(2c^3d^{-2}y^3)

simplify

(c^{2} d^{3} y^{- 4})^{0} (2 c^{3} d^{- 2} y^{3})

\frac{2 c ^{3} y ^{3}}{d ^{2}}

Solution steps

(c^{2} d^{3} y^{- 4})^{0} (2 c^{3} d^{- 2} y^{3})

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

(c^{2} d^{3} y^{- 4})^{0} = 1

= 1 \cdot 2 c^{3} d^{- 2} y^{3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

d^{- 2} = \frac{1}{d ^{2}}

= 1 \cdot 2 c^{3} \frac{1}{d ^{2}} y^{3}

Multiply the numbers:

1 \cdot 2 = 2

= 2 c^{3} \frac{1}{d ^{2}} y^{3}

= 2 c^{3} y^{3} \frac{1}{d ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 c ^{3} y ^{3} \cdot 1}{d ^{2}}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2 c ^{3} y ^{3}}{d ^{2}}

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What is (c^2d^3y^{-4})^0(2c^3d^{-2}y^3) ?
The solution to (c^2d^3y^{-4})^0(2c^3d^{-2}y^3) is (2c^3y^3)/(d^2)