What is factor x^4-3x^3-6x^2+28x-24 ?

The solution to factor x^4-3x^3-6x^2+28x-24 is (x-2)^3(x+3)

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factor x^4-3x^3-6x^2+28x-24

factor

x^{4} - 3 x^{3} - 6 x^{2} + 28 x - 24

(x - 2)^{3} (x + 3)

Solution steps

x^{4} - 3 x^{3} - 6 x^{2} + 28 x - 24

Use the rational root theorem

= (x - 2) \frac{x ^{4} - 3 x ^{3} - 6 x ^{2} + 28 x - 24}{x - 2}

\frac{x ^{4} - 3 x ^{3} - 6 x ^{2} + 28 x - 24}{x - 2} = x^{3} - x^{2} - 8 x + 12

= (x - 2) (x^{3} - x^{2} - 8 x + 12)

Factor

x^{3} - x^{2} - 8 x + 12 : (x - 2) (x - 2) (x + 3)

= (x - 2) (x - 2) (x - 2) (x + 3)

Apply exponent rule:

aaa = a^{3}

(x - 2) (x - 2) (x - 2) = (x - 2)^{3}

= (x - 2)^{3} (x + 3)

lo g_{\frac{1}{3}} (\frac{1}{81})

1.5 u^{2} v^{4} - 2.5 u^{3} v^{5} + 0.5 u^{4} v^{2}

\frac{5 ^{2}}{5 ^{5}}

212 - 375 + 27

32 x^{9} y^{3} - 8 x^{7} y^{5}

What is factor x^4-3x^3-6x^2+28x-24 ?
The solution to factor x^4-3x^3-6x^2+28x-24 is (x-2)^3(x+3)