What is ((n+1)!(n+2))/((n-1)!) ?

The solution to ((n+1)!(n+2))/((n-1)!) is (n+1)n(n+2)

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simplify ((n+1)!(n+2))/((n-1)!)

simplify

\frac{( n + 1 ) ! ( n + 2 )}{( n - 1 ) !}

(n + 1) n (n + 2)

Solution steps

\frac{( n + 1 ) ! ( n + 2 )}{( n - 1 ) !}

Cancel the factorials:

\frac{n !}{( n - m ) !} = n \cdot (n - 1) \dots (n - m + 1), n > m

\frac{( n + 1 ) !}{( n - 1 ) !} = (n + 1) n

= (n + 1) n (n + 2)

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What is ((n+1)!(n+2))/((n-1)!) ?
The solution to ((n+1)!(n+2))/((n-1)!) is (n+1)n(n+2)