What is sin^4(a)+sin^2(a)cos^2(a)-sin^2(a) ?

The solution to sin^4(a)+sin^2(a)cos^2(a)-sin^2(a) is 0

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simplify sin^4(a)+sin^2(a)cos^2(a)-sin^2(a)

simplify

sin^{4} (a) + sin^{2} (a) cos^{2} (a) - sin^{2} (a)

0

Solution steps

sin^{4} (a) + sin^{2} (a) cos^{2} (a) - sin^{2} (a)

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= sin^{2} (a) (- 1 + 1)

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - cos^{2} (x) = sin^{2} (x)

= sin^{2} (a) (sin^{2} (a) - sin^{2} (a))

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - sin^{2} (x) = cos^{2} (x)

= sin^{2} (a) (cos^{2} (a) - cos^{2} (a))

Factor

sin^{4} (a) + sin^{2} (a) cos^{2} (a) - sin^{2} (a) : sin^{2} (a) (sin^{2} (a) + cos^{2} (a) - 1)

= sin^{2} (a) (sin^{2} (a) + cos^{2} (a) - 1)

= 0

d (\frac{x ^{6}}{3 - 2 x})

cos (x) - 2 cos^{2} (x) + 1

(2 b^{2} - 2 - 5 b + 6 b^{3}) (3 + 3 b^{2} - b)

\frac{a}{( a ^{2} + b ^{5} )}

2 x y (\frac{1}{2} + x - 2)

What is sin^4(a)+sin^2(a)cos^2(a)-sin^2(a) ?
The solution to sin^4(a)+sin^2(a)cos^2(a)-sin^2(a) is 0