What is (3y^{-4}z^6)^{-4} ?

The solution to (3y^{-4}z^6)^{-4} is (y^{16})/(81z^{24)}

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simplify (3y^{-4}z^6)^{-4}

simplify

(3 y^{- 4} z^{6})^{- 4}

\frac{y ^{16}}{81 z ^{24}}

Solution steps

(3 y^{- 4} z^{6})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(3 y^{- 4} z^{6})^{- 4} = \frac{1}{( 3 y ^{- 4} z ^{6} ) ^{4}}

= \frac{1}{( 3 y ^{- 4} z ^{6} ) ^{4}}

Simplify

(3 y^{- 4} z^{6})^{4} : \frac{81 z ^{24}}{y ^{16}}

= \frac{1}{\frac{81 z ^{24}}{y ^{16}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{16}}{81 z ^{24}}

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What is (3y^{-4}z^6)^{-4} ?
The solution to (3y^{-4}z^6)^{-4} is (y^{16})/(81z^{24)}