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Popular >

simplify (2d^{-7})^4

Solution

simplify

(2 d^{- 7})^{4}

Solution

\frac{16}{d ^{28}}

Solution steps

(2 d^{- 7})^{4}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(2 d^{- 7})^{4} = 2^{4} (d^{- 7})^{4}

= 2^{4} (d^{- 7})^{4}

2^{4} = 16

= 16 (d^{- 7})^{4}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

(d^{- 7})^{4} = d^{- 7 \cdot 4}

= 16 d^{- 7 \cdot 4}

Multiply the numbers:

7 \cdot 4 = 28

= 16 d^{- 28}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

d^{- 28} = \frac{1}{d ^{28}}

= 16 \cdot \frac{1}{d ^{28}}

Simplify

16 \cdot \frac{1}{d ^{28}} : \frac{16}{d ^{28}}

= \frac{16}{d ^{28}}

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Frequently Asked Questions (FAQ)

What is (2d^{-7})^4 ?
The solution to (2d^{-7})^4 is (16)/(d^{28)}