What is factor 21y^2+4y-1 ?

The solution to factor 21y^2+4y-1 is (7y-1)(3y+1)

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factor 21y^2+4y-1

factor

21 y^{2} + 4 y - 1

(7 y - 1) (3 y + 1)

Solution steps

21 y^{2} + 4 y - 1

Break the expression into groups

= (21 y^{2} - 3 y) + (7 y - 1)

Factor out

3 y

from

21 y^{2} - 3 y : 3 y (7 y - 1)

= 3 y (7 y - 1) + (7 y - 1)

Factor out common term

(7 y - 1) : (7 y - 1) (3 y + 1)

= (7 y - 1) (3 y + 1)

3 - 2 e^{- 0} 0.25 x

(x + 2) (x + 3) (x + 4) (x + 5) - 24

x^{3} y^{3} + 1

3 x^{- x} - 4

(4 p)^{- 3}