What is 2((a^2+1}{(a^2)})-(\frac{a-1)/a)-7 ?

The solution to 2((a^2+1}{(a^2)})-(\frac{a-1)/a)-7 is (2(a^2+1)}{a^2}-\frac{a-1)/a-7

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simplify 2((a^2+1}{(a^2)})-(\frac{a-1)/a)-7

simplify

2 (\frac{a ^{2} + 1}{( a ^{2} )}) - (\frac{a - 1}{a}) - 7

\frac{2 ( a ^{2} + 1 )}{a ^{2}} - \frac{a - 1}{a} - 7

Solution steps

2 (\frac{a ^{2} + 1}{a ^{2}}) - (\frac{a - 1}{a}) - 7

Apply rule:

- (a) = - a

- (\frac{a - 1}{a}) = - \frac{a - 1}{a}

= 2 \cdot \frac{a ^{2} + 1}{a ^{2}} - \frac{a - 1}{a} - 7

Simplify

2 \cdot \frac{a ^{2} + 1}{a ^{2}} : \frac{2 ( a ^{2} + 1 )}{a ^{2}}

= \frac{2 ( a ^{2} + 1 )}{a ^{2}} - \frac{a - 1}{a} - 7

(4 - 4 y^{2})^{3}

\frac{( n ^{2} - 5 n - 14 )}{( n ^{2} - 9 n + 14 )}

35 y^{2} + 13 y - 12

a^{3} + 27 b^{3}

[35 \cdot 3 - x^{3}] + 34

What is 2((a^2+1}{(a^2)})-(\frac{a-1)/a)-7 ?
The solution to 2((a^2+1}{(a^2)})-(\frac{a-1)/a)-7 is (2(a^2+1)}{a^2}-\frac{a-1)/a-7