What is ((12p^3-12p^2))/(9p^2-9p) ?

The solution to ((12p^3-12p^2))/(9p^2-9p) is (4p)/3

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simplify ((12p^3-12p^2))/(9p^2-9p)

simplify

\frac{( 12 p ^{3} - 12 p ^{2} )}{9 p ^{2} - 9 p}

\frac{4 p}{3}

Solution steps

\frac{12 p ^{3} - 12 p ^{2}}{9 p ^{2} - 9 p}

Factor

12 p^{3} - 12 p^{2} : 12 p^{2} (p - 1)

= \frac{12 p ^{2} ( p - 1 )}{9 p ^{2} - 9 p}

Factor

9 p^{2} - 9 p : 9 p (p - 1)

= \frac{12 p ^{2} ( p - 1 )}{9 p ( p - 1 )}

Cancel the common factor:

p - 1

= \frac{12 p ^{2}}{9 p}

Factor the number:

12 = 3 \cdot 4

= \frac{3 \cdot 4 p ^{2}}{9 p}

Factor the number:

9 = 3 \cdot 3

= \frac{3 \cdot 4 p ^{2}}{3 \cdot 3 p}

Cancel the common factor:

3

= \frac{4 p ^{2}}{3 p}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

p^{2} = pp

= \frac{4 pp}{3 p}

Cancel the common factor:

p

= \frac{4 p}{3}

(2 a^{2} \cdot 2)^{\frac{3}{2}}

\frac{( x ^{- 6} )}{( x ^{12} )}

[(2 x - y)^{2} - (2 x + y)^{2}]^{2}

a + b + a^{8} + b

\frac{( e ^{- x} ) ^{2}}{y}

What is ((12p^3-12p^2))/(9p^2-9p) ?
The solution to ((12p^3-12p^2))/(9p^2-9p) is (4p)/3