What is 8x+[9x{6x(5x-4x)}]+14x-{11x[7x(3x-2x)]} ?

The solution to 8x+[9x{6x(5x-4x)}]+14x-{11x[7x(3x-2x)]} is 22x-23x^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 8x+[9x{6x(5x-4x)}]+14x-{11x[7x(3x-2x)]}

simplify

8 x + [9 x {6 x (5 x - 4 x)}] + 14 x - {11 x [7 x (3 x - 2 x)]}

22 x - 23 x^{3}

Solution steps

8 x + (9 x (6 x (5 x - 4 x))) + 14 x - (11 x (7 x (3 x - 2 x)))

Simplify

8 x + (9 x (6 x (5 x - 4 x))) + 14 x - (11 x (7 x (3 x - 2 x))) : 8 x + 9 x (6 x (5 x - 4 x)) + 14 x - 11 x (7 x (3 x - 2 x))

= 8 x + 9 x \cdot 6 x (5 x - 4 x) + 14 x - 11 x \cdot 7 x (3 x - 2 x)

Group like terms

= 8 x + 14 x + 9 x \cdot 6 x (5 x - 4 x) - 11 x \cdot 7 x (3 x - 2 x)

Add similar elements:

8 x + 14 x = 22 x

= 22 x + 9 x \cdot 6 x (5 x - 4 x) - 11 x \cdot 7 x (3 x - 2 x)

9 x \cdot 6 x (5 x - 4 x) = 54 x^{3}

11 x \cdot 7 x (3 x - 2 x) = 77 x^{3}

= 22 x + 54 x^{3} - 77 x^{3}

Add similar elements:

54 x^{3} - 77 x^{3} = - 23 x^{3}

= 22 x - 23 x^{3}

(2 x - 3 y + z)^{2}

\frac{( 10 x - 5 )}{( 5 x )}

(0.1 x - 0.2 y)^{3}

4 (\frac{5 - 1}{2 x})^{2}

\frac{( m ^{15} \cdot x \cdot m ^{16} )}{( m ^{23} )}

What is 8x+[9x{6x(5x-4x)}]+14x-{11x[7x(3x-2x)]} ?
The solution to 8x+[9x{6x(5x-4x)}]+14x-{11x[7x(3x-2x)]} is 22x-23x^3