What is ((2(f^4)^2f^2))/((8f^{12))} ?

The solution to ((2(f^4)^2f^2))/((8f^{12))} is 1/(4f^2)

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simplify ((2(f^4)^2f^2))/((8f^{12))}

simplify

\frac{( 2 ( f ^{4} ) ^{2} f ^{2} )}{( 8 f ^{12} )}

\frac{1}{4 f ^{2}}

Solution steps

\frac{2 ( f ^{4} ) ^{2} f ^{2}}{8 f ^{12}}

Simplify

(f^{4})^{2} : f^{8}

= \frac{2 f ^{8} f ^{2}}{8 f ^{12}}

Factor the number:

8 = 2 \cdot 4

= \frac{2 f ^{8} f ^{2}}{2 \cdot 4 f ^{12}}

Cancel the common factor:

2

= \frac{f ^{8} f ^{2}}{4 f ^{12}}

Simplify

\frac{f ^{8}}{f ^{12}} : \frac{1}{f ^{4}}

= \frac{f ^{2}}{4 f ^{4}}

Simplify

\frac{f ^{2}}{f ^{4}} : \frac{1}{f ^{2}}

= \frac{1}{4 f ^{2}}

2 x^{4} + 50 x^{2} \cdot y^{2} + 1250 y^{4}

1^{p + q}

x^{6} - y^{2}

2 (x + y)^{2} - 9 (x + y) - 5

4 x^{2} - 39 x + 27

What is ((2(f^4)^2f^2))/((8f^{12))} ?
The solution to ((2(f^4)^2f^2))/((8f^{12))} is 1/(4f^2)