What is (4xy(y^2+6y-16))/(2x(y+8)) ?

The solution to (4xy(y^2+6y-16))/(2x(y+8)) is 2y(y-2)

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simplify (4xy(y^2+6y-16))/(2x(y+8))

simplify

\frac{4 x y ( y ^{2} + 6 y - 16 )}{2 x ( y + 8 )}

2 y (y - 2)

Solution steps

\frac{4 x y ( y ^{2} + 6 y - 16 )}{2 x ( y + 8 )}

Cancel the common factor:

x

= \frac{4 y ( y ^{2} + 6 y - 16 )}{2 ( y + 8 )}

Factor the number:

4 = 2 \cdot 2

= \frac{2 \cdot 2 y ( y ^{2} + 6 y - 16 )}{2 ( y + 8 )}

Cancel the common factor:

2

= \frac{2 y ( y ^{2} + 6 y - 16 )}{y + 8}

Factor

y^{2} + 6 y - 16 : (y - 2) (y + 8)

= \frac{2 y ( y - 2 ) ( y + 8 )}{y + 8}

Cancel the common factor:

y + 8

= 2 y (y - 2)

x^{2} \cdot y - x \cdot y^{2} + 5 x - 5 y

(z - 5)^{3}

(\frac{- a}{b})^{- 4}

(x - y)^{3} - 1

(x - 2 y + 2) 2

What is (4xy(y^2+6y-16))/(2x(y+8)) ?
The solution to (4xy(y^2+6y-16))/(2x(y+8)) is 2y(y-2)