What are the solutions to the equation 5x^2-4x+6=0 ?

The solutions to the equation 5x^2-4x+6=0 are x= 2/5+i(sqrt(26))/5 ,x= 2/5-i(sqrt(26))/5

Find the zeros of 5x^2-4x+6=0

The zeros of 5x^2-4x+6=0 are x= 2/5+i(sqrt(26))/5 ,x= 2/5-i(sqrt(26))/5

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5 x^{2} - 4 x + 6 = 0

x = \frac{2}{5} + i \frac{26}{5}, x = \frac{2}{5} - i \frac{26}{5}

Solution steps

5 x^{2} - 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

Simplify

(- 4)^{2} - 4 \cdot 5 \cdot 6 : 226 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 26 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 26 i}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 2 26 i}{2 \cdot 5}

x = \frac{- ( - 4 ) + 2 26 i}{2 \cdot 5} : \frac{2}{5} + i \frac{26}{5}

x = \frac{- ( - 4 ) - 2 26 i}{2 \cdot 5} : \frac{2}{5} - i \frac{26}{5}

The solutions to the quadratic equation are:

x = \frac{2}{5} + i \frac{26}{5}, x = \frac{2}{5} - i \frac{26}{5}

x^{4} - 65 x^{2} + 64

3 (2 n - 2) - 1 = \frac{9}{4}

\frac{11 !}{( 11 - 6 ) !}

4 (y - 8) = - 20

4 w^{2} = 11 w - 6

What are the solutions to the equation 5x^2-4x+6=0 ?
The solutions to the equation 5x^2-4x+6=0 are x= 2/5+i(sqrt(26))/5 ,x= 2/5-i(sqrt(26))/5
Find the zeros of 5x^2-4x+6=0
The zeros of 5x^2-4x+6=0 are x= 2/5+i(sqrt(26))/5 ,x= 2/5-i(sqrt(26))/5