What is expand (3x^4+2x*y^2)^3 ?

The solution to expand (3x^4+2x*y^2)^3 is 27x^{12}+54x^9y^2+36x^6y^4+8x^3y^6

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expand (3x^4+2x*y^2)^3

expand

(3 x^{4} + 2 x \cdot y^{2})^{3}

27 x^{12} + 54 x^{9} y^{2} + 36 x^{6} y^{4} + 8 x^{3} y^{6}

Solution steps

(3 x^{4} + 2 x y^{2})^{3}

Apply Perfect Cube Formula:

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

(3 x^{4} + 2 x y^{2})^{3} = (3 x^{4})^{3} + 3 (3 x^{4})^{2} \cdot 2 x y^{2} + 3 \cdot 3 x^{4} (2 x y^{2})^{2} + (2 x y^{2})^{3}

= (3 x^{4})^{3} + 3 (3 x^{4})^{2} \cdot 2 x y^{2} + 3 \cdot 3 x^{4} (2 x y^{2})^{2} + (2 x y^{2})^{3}

Simplify

(3 x^{4})^{3} + 3 (3 x^{4})^{2} \cdot 2 x y^{2} + 3 \cdot 3 x^{4} (2 x y^{2})^{2} + (2 x y^{2})^{3} : 27 x^{12} + 54 x^{9} y^{2} + 36 x^{6} y^{4} + 8 x^{3} y^{6}

= 27 x^{12} + 54 x^{9} y^{2} + 36 x^{6} y^{4} + 8 x^{3} y^{6}

\frac{x}{( sin ( x ) ) ^{3}}

2 x + 35 - x^{2}

(7 p + 8) - (3 p + 3)

p^{2} \cdot (p^{5})^{2}

(4 a + 9 b)^{3}

What is expand (3x^4+2x*y^2)^3 ?
The solution to expand (3x^4+2x*y^2)^3 is 27x^{12}+54x^9y^2+36x^6y^4+8x^3y^6