What is ((z-i)^3)/((z^2+1)) ?

The solution to ((z-i)^3)/((z^2+1)) is ((z-i)^3)/(z^2+1)

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simplify ((z-i)^3)/((z^2+1))

simplify

\frac{( z - i ) ^{3}}{( z ^{2} + 1 )}

\frac{( z - i ) ^{3}}{z ^{2} + 1}

Solution steps

\frac{( z - i ) ^{3}}{( z ^{2} + 1 )}

Remove parentheses:

(a) = a

= \frac{( z - i ) ^{3}}{z ^{2} + 1}

\frac{( 36 x + 16 y )}{4}

4 x^{2} - 6 n + 6

a^{17} + b^{17}

x^{2} y^{2} - x^{2} y + x y

100 - x^{2} y^{2}

What is ((z-i)^3)/((z^2+1)) ?
The solution to ((z-i)^3)/((z^2+1)) is ((z-i)^3)/(z^2+1)