What is (((x/y)-(y/x)))/((x^2-y^2)) ?

The solution to (((x/y)-(y/x)))/((x^2-y^2)) is 1/(xy)

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simplify (((x/y)-(y/x)))/((x^2-y^2))

simplify

\frac{( ( \frac{x}{y} ) - ( \frac{y}{x} ) )}{( x ^{2} - y ^{2} )}

\frac{1}{x y}

Solution steps

\frac{( \frac{x}{y} ) - ( \frac{y}{x} )}{x ^{2} - y ^{2}}

Simplify

(\frac{x}{y}) - (\frac{y}{x}) : \frac{x}{y} - \frac{y}{x}

= \frac{\frac{x}{y} - \frac{y}{x}}{x ^{2} - y ^{2}}

Join

\frac{x}{y} - \frac{y}{x} : \frac{x ^{2} - y ^{2}}{x y}

= \frac{\frac{x ^{2} - y ^{2}}{x y}}{x ^{2} - y ^{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{x ^{2} - y ^{2}}{x y ( x ^{2} - y ^{2} )}

Cancel the common factor:

x^{2} - y^{2}

= \frac{1}{x y}

(2^{n})^{m}

(w^{2} z^{3})^{4}

\frac{1}{( 3 e ^{x} + e ^{- 1} )}

\frac{7 x}{4 + 70}

(1 + r)^{10}

What is (((x/y)-(y/x)))/((x^2-y^2)) ?
The solution to (((x/y)-(y/x)))/((x^2-y^2)) is 1/(xy)