What is (((4y^6)}{(9z^8)})^{\frac{-1)/2} ?

The solution to (((4y^6)}{(9z^8)})^{\frac{-1)/2} is (3z^4)/(2y^3)

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simplify (((4y^6)}{(9z^8)})^{\frac{-1)/2}

simplify

(\frac{( 4 y ^{6} )}{( 9 z ^{8} )})^{\frac{- 1}{2}}

\frac{3 z ^{4}}{2 y ^{3}}

Solution steps

(\frac{4 y ^{6}}{9 z ^{8}})^{\frac{- 1}{2}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 4 y ^{6} ) ^{\frac{- 1}{2}}}{( 9 z ^{8} ) ^{\frac{- 1}{2}}}

Simplify

(4 y^{6})^{\frac{- 1}{2}} : \frac{1}{2 y ^{3}}

= \frac{\frac{1}{2 y ^{3}}}{( 9 z ^{8} ) ^{\frac{- 1}{2}}}

Simplify

(9 z^{8})^{\frac{- 1}{2}} : \frac{1}{3 z ^{4}}

= \frac{\frac{1}{2 y ^{3}}}{\frac{1}{3 z ^{4}}}

Simplify

\frac{\frac{1}{2 y ^{3}}}{\frac{1}{3 z ^{4}}} : \frac{3 z ^{4}}{2 y ^{3}}

= \frac{3 z ^{4}}{2 y ^{3}}

(a) (a + d) (a + 2 d)

2 x^{2} - 4 x - 2 y^{2} - 4 y

2 - 3 x^{4} x^{22}

9 x + x^{2} x - 2

4 x^{2} + 9 y^{2} + 12 x y

What is (((4y^6)}{(9z^8)})^{\frac{-1)/2} ?
The solution to (((4y^6)}{(9z^8)})^{\frac{-1)/2} is (3z^4)/(2y^3)