What is (4/n)-(6/(n+2)) ?

The solution to (4/n)-(6/(n+2)) is (-2n+8)/(n(n+2))

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simplify (4/n)-(6/(n+2))

simplify

(\frac{4}{n}) - (\frac{6}{n + 2})

\frac{- 2 n + 8}{n ( n + 2 )}

Solution steps

(\frac{4}{n}) - (\frac{6}{n + 2})

Remove parentheses:

(a) = a

= \frac{4}{n} - \frac{6}{n + 2}

Least Common Multiplier of

n, n + 2 : n (n + 2)

Adjust Fractions based on the LCM

= \frac{4 ( n + 2 )}{n ( n + 2 )} - \frac{6 n}{( n + 2 ) n}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 ( n + 2 ) - 6 n}{n ( n + 2 )}

Expand

4 (n + 2) - 6 n : - 2 n + 8

= \frac{- 2 n + 8}{n ( n + 2 )}

\frac{( - x ) ^{7}}{( - x ) ^{4}}

(\frac{x ^{2} + 2}{x})^{2}

\frac{1}{9} \cdot x^{2} + \frac{4}{15} + \frac{4}{25} \cdot x

4 a^{2} - 9 b^{2} - (2 a - 3 b)

2 (0.1 x - 3 y)