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Frequently Asked Questions (FAQ)
What is (1/2*x^2+2/3*y^2)^2-(1/2*x^2-2/3*y^2)^2 ?
The solution to (1/2*x^2+2/3*y^2)^2-(1/2*x^2-2/3*y^2)^2 is (4x^2y^2)/3