What is factor 6x^3+3x^2-5x+1 ?

The solution to factor 6x^3+3x^2-5x+1 is (2x-1)(3x^2+3x-1)

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factor 6x^3+3x^2-5x+1

factor

6 x^{3} + 3 x^{2} - 5 x + 1

(2 x - 1) (3 x^{2} + 3 x - 1)

Solution steps

6 x^{3} + 3 x^{2} - 5 x + 1

Use the rational root theorem

= (2 x - 1) \frac{6 x ^{3} + 3 x ^{2} - 5 x + 1}{2 x - 1}

\frac{6 x ^{3} + 3 x ^{2} - 5 x + 1}{2 x - 1} = 3 x^{2} + 3 x - 1

= (2 x - 1) (3 x^{2} + 3 x - 1)

\frac{ln ( 1 )}{x ^{2}}

(5 x - 8 y)^{3}

\frac{( 4 x \cdot y ^{2} + 2 x ^{2} \cdot y ^{2} - 2 x \cdot y ^{3} )}{( 2 x ^{2} \cdot y ^{2} )}

\frac{( 8 )}{( 3 x )}

9 u^{2} v^{4} - u^{2} v^{2}

What is factor 6x^3+3x^2-5x+1 ?
The solution to factor 6x^3+3x^2-5x+1 is (2x-1)(3x^2+3x-1)