What is (2/((x^2+1)))e^logx ?

The solution to (2/((x^2+1)))e^logx is (2e^lxog)/(x^2+1)

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simplify (2/((x^2+1)))e^logx

simplify

(\frac{2}{( x ^{2} + 1 )}) e^{l} o gx

\frac{2 e ^{l} x o g}{x ^{2} + 1}

Solution steps

(\frac{2}{x ^{2} + 1}) e^{l} o gx

Remove parentheses:

(a) = a

= \frac{2}{x ^{2} + 1} e^{l} o gx

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 e ^{l} o gx}{x ^{2} + 1}

(x - 1)^{3} (x + 1)^{2}

\frac{( a + b )}{( \frac{a}{12} + \frac{b}{6} )}

(\frac{4}{5 \cdot p - 3 q})^{2}

(x^{3} y^{3})^{2} + (2 x^{2} y^{2})^{3}

\frac{- 5}{( 3 - 2 x )}

What is (2/((x^2+1)))e^logx ?
The solution to (2/((x^2+1)))e^logx is (2e^lxog)/(x^2+1)