What is (a^{-5}+b)^{-4} ?

The solution to (a^{-5}+b)^{-4} is (a^{20})/((a^5b+1)^4)

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simplify (a^{-5}+b)^{-4}

simplify

(a^{- 5} + b)^{- 4}

\frac{a ^{20}}{( a ^{5} b + 1 ) ^{4}}

Solution steps

(a^{- 5} + b)^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(a^{- 5} + b)^{- 4} = \frac{1}{( a ^{- 5} + b ) ^{4}}

= \frac{1}{( a ^{- 5} + b ) ^{4}}

Simplify

(a^{- 5} + b)^{4} : \frac{( b a ^{5} + 1 ) ^{4}}{a ^{20}}

= \frac{1}{\frac{( b a ^{5} + 1 ) ^{4}}{a ^{20}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{a ^{20}}{( a ^{5} b + 1 ) ^{4}}

\frac{1}{1} + \frac{1}{s ^{2}}

(3 x - 1)^{9}

(0.006 - x) (0.004 - x)

\frac{1 + 2 ( 4 + 1 )}{5 ^{1} - ( 5 x - 2 )}

a [(- 28) - (+ 42)] - (- 13)

What is (a^{-5}+b)^{-4} ?
The solution to (a^{-5}+b)^{-4} is (a^{20})/((a^5b+1)^4)