What is ((x+1}{(2x)})^7*(\frac{2x-1)/x)^5 ?

The solution to ((x+1}{(2x)})^7*(\frac{2x-1)/x)^5 is ((x+1)^7(2x-1)^5)/(128x^{12)}

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simplify ((x+1}{(2x)})^7*(\frac{2x-1)/x)^5

simplify

(\frac{x + 1}{( 2 x )})^{7} \cdot (\frac{2 x - 1}{x})^{5}

\frac{( x + 1 ) ^{7} ( 2 x - 1 ) ^{5}}{128 x ^{12}}

Solution steps

(\frac{x + 1}{2 x})^{7} (\frac{2 x - 1}{x})^{5}

Simplify

(\frac{x + 1}{2 x})^{7} : \frac{( x + 1 ) ^{7}}{128 x ^{7}}

= \frac{( x + 1 ) ^{7}}{128 x ^{7}} (\frac{2 x - 1}{x})^{5}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

(\frac{2 x - 1}{x})^{5} = \frac{( 2 x - 1 ) ^{5}}{x ^{5}}

= \frac{( x + 1 ) ^{7}}{128 x ^{7}} \cdot \frac{( 2 x - 1 ) ^{5}}{x ^{5}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x + 1 ) ^{7} ( 2 x - 1 ) ^{5}}{128 x ^{7} x ^{5}}

Simplify

x^{7} x^{5} : x^{12}

= \frac{( x + 1 ) ^{7} ( 2 x - 1 ) ^{5}}{128 x ^{12}}

\frac{( 200 x - 300 )}{100}

f (1)^{2}

(3 x^{2} - x)^{7}

(\frac{2}{3 x ^{2}})^{4}

12 cos^{2} (a) + 32 sin^{2} (a)

What is ((x+1}{(2x)})^7*(\frac{2x-1)/x)^5 ?
The solution to ((x+1}{(2x)})^7*(\frac{2x-1)/x)^5 is ((x+1)^7(2x-1)^5)/(128x^{12)}