What is ((6p^2-2p))/((3p^2-p+3p-1)) ?

The solution to ((6p^2-2p))/((3p^2-p+3p-1)) is (2p)/(p+1)

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simplify ((6p^2-2p))/((3p^2-p+3p-1))

simplify

\frac{( 6 p ^{2} - 2 p )}{( 3 p ^{2} - p + 3 p - 1 )}

\frac{2 p}{p + 1}

Solution steps

\frac{6 p ^{2} - 2 p}{3 p ^{2} - p + 3 p - 1}

Add similar elements:

- p + 3 p = 2 p

= \frac{6 p ^{2} - 2 p}{3 p ^{2} + 2 p - 1}

Factor

6 p^{2} - 2 p : 2 p (3 p - 1)

= \frac{2 p ( 3 p - 1 )}{3 p ^{2} + 2 p - 1}

Factor

3 p^{2} + 2 p - 1 : (3 p - 1) (p + 1)

= \frac{2 p ( 3 p - 1 )}{( 3 p - 1 ) ( p + 1 )}

Cancel the common factor:

3 p - 1

= \frac{2 p}{p + 1}

36 x^{2} - 5 x y - y^{2}

71 + cot^{2} (a) 1 + tan^{2} (a)

3 x^{\frac{1}{2}} \cdot 5 x^{\frac{1}{2}}

49 a^{4} - 42 a^{2} b + 9 b^{2}

\frac{- x}{x ^{2}}

What is ((6p^2-2p))/((3p^2-p+3p-1)) ?
The solution to ((6p^2-2p))/((3p^2-p+3p-1)) is (2p)/(p+1)