What is l^{-1}*{s/(((s-1)^4))} ?

The solution to l^{-1}*{s/(((s-1)^4))} is s/(l(s-1)^4)

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simplify l^{-1}*{s/(((s-1)^4))}

simplify

l^{- 1} \cdot ⎩ ⎨ ⎧ \frac{s}{( ( s - 1 ) ^{4} )} ⎭ ⎬ ⎫

\frac{s}{l ( s - 1 ) ^{4}}

Solution steps

l^{- 1} (\frac{s}{( s - 1 ) ^{4}})

Apply rule:

(a) = a

(\frac{s}{( s - 1 ) ^{4}}) = \frac{s}{( s - 1 ) ^{4}}

= l^{- 1} \frac{s}{( s - 1 ) ^{4}}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

l^{- 1} = \frac{1}{l}

= \frac{1}{l} \cdot \frac{s}{( s - 1 ) ^{4}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot s}{l ( s - 1 ) ^{4}}

Apply rule:

1 \cdot a = a

1 \cdot s = s

= \frac{s}{l ( s - 1 ) ^{4}}

2 y + x y + 2 x y + 2

(64 x^{3})^{2}

25 (x y)^{4} + 18 (x^{2} y^{2})^{2} + (- 63 x^{4}) y^{4}

(5 + y)^{3}

(d^{4})^{\frac{1}{3}}

What is l^{-1}*{s/(((s-1)^4))} ?
The solution to l^{-1}*{s/(((s-1)^4))} is s/(l(s-1)^4)