What is factor 16x^2+8x+1-9y^2 ?

The solution to factor 16x^2+8x+1-9y^2 is (4x+1+3y)(4x+1-3y)

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factor 16x^2+8x+1-9y^2

factor

16 x^{2} + 8 x + 1 - 9 y^{2}

(4 x + 1 + 3 y) (4 x + 1 - 3 y)

Solution steps

16 x^{2} + 8 x + 1 - 9 y^{2}

Factor

16 x^{2} + 8 x + 1 : (4 x + 1)^{2}

= (4 x + 1)^{2} - 9 y^{2}

Simplify

9 y^{2} : (3 y)^{2}

= (4 x + 1)^{2} - (3 y)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 x + 1)^{2} - (3 y)^{2} = ((4 x + 1) + 3 y) ((4 x + 1) - 3 y)

= ((4 x + 1) + 3 y) ((4 x + 1) - 3 y)

Apply rule:

(a) = a

(4 x + 1) = 4 x + 1

= (4 x + 1 + 3 y) (4 x + 1 - 3 y)

(\frac{3}{2} \cdot x + \frac{2}{3})^{2}

a^{0} b^{0} + c^{0} + 4 a^{0}

- 1 + 2 cos^{2} (x)

\frac{1}{( d ^{2} + d + 1 ) ( sin ( x ) )}

(\frac{a}{2} + \frac{b}{2})^{3}

What is factor 16x^2+8x+1-9y^2 ?
The solution to factor 16x^2+8x+1-9y^2 is (4x+1+3y)(4x+1-3y)