What is (4p^2*2q-3r-6)^{-3} ?

The solution to (4p^2*2q-3r-6)^{-3} is 1/((8p^2q-3r-6)^3)

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simplify (4p^2*2q-3r-6)^{-3}

simplify

(4 p^{2} \cdot 2 q - 3 r - 6)^{- 3}

\frac{1}{( 8 p ^{2} q - 3 r - 6 ) ^{3}}

Solution steps

(4 p^{2} \cdot 2 q - 3 r - 6)^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(4 p^{2} \cdot 2 q - 3 r - 6)^{- 3} = \frac{1}{( 4 p ^{2} \cdot 2 q - 3 r - 6 ) ^{3}}

= \frac{1}{( 4 p ^{2} \cdot 2 q - 3 r - 6 ) ^{3}}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{1}{( 8 p ^{2} q - 3 r - 6 ) ^{3}}

2 x - 5 x - x + 2 x

\frac{3}{2} e^{x} - \frac{2}{2} e^{x}

\frac{( a ^{2} - 5 )}{( a - 5 )}

\frac{7 c ^{5} \cdot 3 c ^{2}}{10 c ^{7}}

(a - b) (a^{2} + b^{2}) + (a + b) (a^{2} - b^{2})

What is (4p^2*2q-3r-6)^{-3} ?
The solution to (4p^2*2q-3r-6)^{-3} is 1/((8p^2q-3r-6)^3)