What is (l^{-1}s)/((s^2+2s+5)^2) ?

The solution to (l^{-1}s)/((s^2+2s+5)^2) is s/(l(s^2+2s+5)^2)

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simplify (l^{-1}s)/((s^2+2s+5)^2)

simplify

\frac{l ^{- 1} s}{( s ^{2} + 2 s + 5 ) ^{2}}

\frac{s}{l ( s ^{2} + 2 s + 5 ) ^{2}}

Solution steps

\frac{l ^{- 1} s}{( s ^{2} + 2 s + 5 ) ^{2}}

Simplify

l^{- 1} s : \frac{s}{l}

= \frac{\frac{s}{l}}{( s ^{2} + 2 s + 5 ) ^{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{s}{l ( s ^{2} + 2 s + 5 ) ^{2}}

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What is (l^{-1}s)/((s^2+2s+5)^2) ?
The solution to (l^{-1}s)/((s^2+2s+5)^2) is s/(l(s^2+2s+5)^2)