What is [((81y^8))/((16x^4))]^{3/4} ?

The solution to [((81y^8))/((16x^4))]^{3/4} is (27y^6)/(8x^3)

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simplify [((81y^8))/((16x^4))]^{3/4}

simplify

[\frac{( 81 y ^{8} )}{( 16 x ^{4} )}]^{\frac{3}{4}}

\frac{27 y ^{6}}{8 x ^{3}}

Solution steps

(\frac{81 y ^{8}}{16 x ^{4}})^{\frac{3}{4}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 81 y ^{8} ) ^{\frac{3}{4}}}{( 16 x ^{4} ) ^{\frac{3}{4}}}

Simplify

(81 y^{8})^{\frac{3}{4}} : 27 y^{6}

= \frac{27 y ^{6}}{( 16 x ^{4} ) ^{\frac{3}{4}}}

Simplify

(16 x^{4})^{\frac{3}{4}} : 8 x^{3}

= \frac{27 y ^{6}}{8 x ^{3}}

\frac{- x ^{3} + 4 x ^{2} - 3}{x - 1}

(i) x^{2} + x - 12

cos^{- 3} (x)

- \frac{4}{5 - x}

x^{3} x

What is [((81y^8))/((16x^4))]^{3/4} ?
The solution to [((81y^8))/((16x^4))]^{3/4} is (27y^6)/(8x^3)