What is factor 64x^4-81y^2 ?

The solution to factor 64x^4-81y^2 is (8x^2+9y)(8x^2-9y)

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factor 64x^4-81y^2

factor

64 x^{4} - 81 y^{2}

(8 x^{2} + 9 y) (8 x^{2} - 9 y)

Solution steps

64 x^{4} - 81 y^{2}

64 x^{4} = (8 x^{2})^{2}

81 y^{2} = (9 y)^{2}

= (8 x^{2})^{2} - (9 y)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(8 x^{2})^{2} - (9 y)^{2} = (8 x^{2} + 9 y) (8 x^{2} - 9 y)

= (8 x^{2} + 9 y) (8 x^{2} - 9 y)

7 n^{2} - x \cdot n

(8 a^{6})^{\frac{1}{3}}

4 x y + 8

2 x^{2} - 4 x + 4 x - 2

∣ x - 1 ∣ + (x + 1)^{- 1}

What is factor 64x^4-81y^2 ?
The solution to factor 64x^4-81y^2 is (8x^2+9y)(8x^2-9y)