What is ((17x^6-x^6))/((2x^3)-(2x)^2*2x) ?

The solution to ((17x^6-x^6))/((2x^3)-(2x)^2*2x) is -(8x^3)/3

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simplify ((17x^6-x^6))/((2x^3)-(2x)^2*2x)

simplify

\frac{( 17 x ^{6} - x ^{6} )}{( 2 x ^{3} ) - ( 2 x ) ^{2} \cdot 2 x}

- \frac{8 x ^{3}}{3}

Solution steps

\frac{17 x ^{6} - x ^{6}}{( 2 x ^{3} ) - ( 2 x ) ^{2} \cdot 2 x}

Apply rule:

(a) = a

(2 x^{3}) = 2 x^{3}

= \frac{17 x ^{6} - x ^{6}}{2 x ^{3} - ( 2 x ) ^{2} \cdot 2 x}

Simplify

2 x^{3} - (2 x)^{2} \cdot 2 x : - 6 x^{3}

= \frac{17 x ^{6} - x ^{6}}{- 6 x ^{3}}

Add similar elements:

17 x^{6} - x^{6} = 16 x^{6}

= \frac{16 x ^{6}}{- 6 x ^{3}}

Factor the number:

16 = 2 \cdot 8

= \frac{2 \cdot 8 x ^{6}}{- 6 x ^{3}}

Factor the number:

6 = 2 \cdot 3

= \frac{2 \cdot 8 x ^{6}}{- 2 \cdot 3 x ^{3}}

Cancel the common factor:

2

= \frac{8 x ^{6}}{- 3 x ^{3}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{6} = x^{3} x^{3}

= \frac{8 x ^{3} x ^{3}}{- 3 x ^{3}}

Cancel the common factor:

x^{3}

= \frac{8 x ^{3}}{- 3}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{8 x ^{3}}{3}

m + b^{6} m - 4 b - m + 2 b^{6} m - 4 b

y^{3} - 9 y^{2} + 18 y

9.81 \frac{m}{s ^{2}}

d^{215} x^{2} - 2 x^{4}

(1.5 - 0.6 v) (- 4.6)

What is ((17x^6-x^6))/((2x^3)-(2x)^2*2x) ?
The solution to ((17x^6-x^6))/((2x^3)-(2x)^2*2x) is -(8x^3)/3