What is factor x^4+x^3-4x-16 ?

The solution to factor x^4+x^3-4x-16 is (x-2)(x+2)(x^2+x+4)

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factor x^4+x^3-4x-16

factor

x^{4} + x^{3} - 4 x - 16

(x - 2) (x + 2) (x^{2} + x + 4)

Solution steps

x^{4} + x^{3} - 4 x - 16

Use the rational root theorem

= (x - 2) \frac{x ^{4} + x ^{3} - 4 x - 16}{x - 2}

\frac{x ^{4} + x ^{3} - 4 x - 16}{x - 2} = x^{3} + 3 x^{2} + 6 x + 8

= (x - 2) (x^{3} + 3 x^{2} + 6 x + 8)

Factor

x^{3} + 3 x^{2} + 6 x + 8 : (x + 2) (x^{2} + x + 4)

= (x - 2) (x + 2) (x^{2} + x + 4)

2 a^{2} + a^{2} - 2 a - 1

f (x) 3 x + 5

f (x) 3 x - 1

\frac{cot ( \frac{x}{4} )}{- sin ^{2} ( x )}

(1 - (1 - x)) (1 - x)^{4}

What is factor x^4+x^3-4x-16 ?
The solution to factor x^4+x^3-4x-16 is (x-2)(x+2)(x^2+x+4)