What are the solutions to the equation -x^2-5x-6=0 ?

The solutions to the equation -x^2-5x-6=0 are x=-3,x=-2

Find the zeros of -x^2-5x-6=0

The zeros of -x^2-5x-6=0 are x=-3,x=-2

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- x^{2} - 5 x - 6 = 0

x = - 3, x = - 2

Solution steps

- x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) (- 6) = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 ( - 1 )}, x_{2} = \frac{- ( - 5 ) - 1}{2 ( - 1 )}

x = \frac{- ( - 5 ) + 1}{2 ( - 1 )} : - 3

x = \frac{- ( - 5 ) - 1}{2 ( - 1 )} : - 2

The solutions to the quadratic equation are:

x = - 3, x = - 2

- \frac{5}{3} + \frac{13}{9} (- 1.1 + 1)

\frac{4 + 2 i}{4 - 2 i}

2 k + 1 > 15

x y^{2} 45 x^{5} y^{5}

x^{2} y^{2} - 4

What are the solutions to the equation -x^2-5x-6=0 ?
The solutions to the equation -x^2-5x-6=0 are x=-3,x=-2
Find the zeros of -x^2-5x-6=0
The zeros of -x^2-5x-6=0 are x=-3,x=-2