What is ((2x+y))/((x^{-1)+2y^{-1})} ?

The solution to ((2x+y))/((x^{-1)+2y^{-1})} is xy

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simplify ((2x+y))/((x^{-1)+2y^{-1})}

simplify

\frac{( 2 x + y )}{( x ^{- 1} + 2 y ^{- 1} )}

x y

Solution steps

\frac{2 x + y}{x ^{- 1} + 2 y ^{- 1}}

Simplify

x^{- 1} + 2 y^{- 1} : \frac{y + 2 x}{x y}

= \frac{2 x + y}{\frac{y + 2 x}{x y}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( 2 x + y ) x y}{y + 2 x}

Cancel

\frac{( 2 x + y ) x y}{y + 2 x} : x y

= x y

3 x^{3} + 8 x^{2} + 3 x - 2

4.5 (3^{2}) - 4.5 n + 3

x^{3} + \frac{3}{2} \cdot x^{2} + \frac{3}{4} \cdot x + \frac{1}{8}

arcsin (\frac{( 1 + x + 1 - x )}{( x )})

m^{556} - 205 - 395300016671 - 2

What is ((2x+y))/((x^{-1)+2y^{-1})} ?
The solution to ((2x+y))/((x^{-1)+2y^{-1})} is xy