What is ((2^{x+1}+2^x))/((2^{x+1)-2^x)} ?

The solution to ((2^{x+1}+2^x))/((2^{x+1)-2^x)} is 3

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simplify ((2^{x+1}+2^x))/((2^{x+1)-2^x)}

simplify

\frac{( 2 ^{x + 1} + 2 ^{x} )}{( 2 ^{x + 1} - 2 ^{x} )}

3

Solution steps

\frac{2 ^{x + 1} + 2 ^{x}}{2 ^{x + 1} - 2 ^{x}}

Factor

2^{x + 1} + 2^{x} : 3 \cdot 2^{x}

= \frac{3 \cdot 2 ^{x}}{2 ^{x + 1} - 2 ^{x}}

Factor

2^{x + 1} - 2^{x} : 2^{x}

= \frac{3 \cdot 2 ^{x}}{2 ^{x}}

Cancel the common factor:

2^{x}

= 3

(a) x^{2} + 11 x + 28

\frac{3 - 1 - ( ( ( 1 - x ) ^{- 1} ) ^{- 1} ) ^{- 1}}{2}

(a^{2} + 1) x^{2} + a^{2} (a^{2} + 2) x - (a^{2} + 1)

x^{2} - 4 3 x + 3

\frac{( c ^{2} + 13 c + 36 )}{( c + 9 )}

What is ((2^{x+1}+2^x))/((2^{x+1)-2^x)} ?
The solution to ((2^{x+1}+2^x))/((2^{x+1)-2^x)} is 3