What are the solutions to the equation 2x^2+6x-8=0 ?

The solutions to the equation 2x^2+6x-8=0 are x=1,x=-4

Find the zeros of 2x^2+6x-8=0

The zeros of 2x^2+6x-8=0 are x=1,x=-4

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2 x^{2} + 6 x - 8 = 0

x = 1, x = - 4

Solution steps

2 x^{2} + 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 8) = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 \cdot 2}, x_{2} = \frac{- 6 - 10}{2 \cdot 2}

x = \frac{- 6 + 10}{2 \cdot 2} : 1

x = \frac{- 6 - 10}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

36 x^{2} + 84 x + 49

5 - x < 3 - x

c^{2}

\frac{56}{x - 1} - \frac{56}{x} \geq 1

5 n^{2} - 4 n - 10 = 15

What are the solutions to the equation 2x^2+6x-8=0 ?
The solutions to the equation 2x^2+6x-8=0 are x=1,x=-4
Find the zeros of 2x^2+6x-8=0
The zeros of 2x^2+6x-8=0 are x=1,x=-4