What is sqrt((81)/(49*x^4*y^{10))} ?

The solution to sqrt((81)/(49*x^4*y^{10))} is 9/(7x^2y^5)

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simplify sqrt((81)/(49x^4y^{10))}

simplify

\frac{81}{49 \cdot x ^{4} \cdot y ^{10}}

\frac{9}{7 x ^{2} y ^{5}}

Solution steps

\frac{81}{49 x ^{4} y ^{10}}

Apply radical rule:

\frac{a}{b} = \frac{a}{b},

assuming

a \geq 0, b \geq 0

= \frac{81}{49 x ^{4} y ^{10}}

81 = 9

= \frac{9}{49 x ^{4} y ^{10}}

Simplify

49 x^{4} y^{10} : 7 x^{2} y^{5}

= \frac{9}{7 x ^{2} y ^{5}}

\frac{( 12 x ^{8} \cdot y ^{3} )}{( - 3 x ^{2} \cdot y )}

(b cos (a))^{2} + (b sin (a))^{2}

a^{5} - a^{3} \cdot b^{2} - a^{2} \cdot b^{3} + b^{5}

(\frac{8}{6} \cdot x^{3} + \frac{5}{11} \cdot y^{2})^{2}

1 x^{3} - 36 x y^{2} + 6 x - 216 y^{2}

What is sqrt((81)/(49*x^4*y^{10))} ?
The solution to sqrt((81)/(49*x^4*y^{10))} is 9/(7x^2y^5)