What is factor 1-9a^2*b^4*c^6*d^8 ?

The solution to factor 1-9a^2*b^4*c^6*d^8 is (1+3ab^2c^3d^4)(1-3ab^2c^3d^4)

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factor 1-9a^2b^4c^6*d^8

factor

1 - 9 a^{2} \cdot b^{4} \cdot c^{6} \cdot d^{8}

(1 + 3 a b^{2} c^{3} d^{4}) (1 - 3 a b^{2} c^{3} d^{4})

Solution steps

1 - 9 a^{2} b^{4} c^{6} d^{8}

1 = 1^{2}

9 a^{2} b^{4} c^{6} d^{8} = (3 a b^{2} c^{3} d^{4})^{2}

= 1^{2} - (3 a b^{2} c^{3} d^{4})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

1^{2} - (3 a b^{2} c^{3} d^{4})^{2} = (1 + 3 a b^{2} c^{3} d^{4}) (1 - 3 a b^{2} c^{3} d^{4})

= (1 + 3 a b^{2} c^{3} d^{4}) (1 - 3 a b^{2} c^{3} d^{4})

343 p^{4} - 7 q^{2}

(5 m^{3})^{2} \cdot 4 m^{4}

f (x) 5 x + 1

d (4 - 3) \cdot y (- 57)

f \cdot 11025 \cdot 1024

What is factor 1-9a^2*b^4*c^6*d^8 ?
The solution to factor 1-9a^2*b^4*c^6*d^8 is (1+3ab^2c^3d^4)(1-3ab^2c^3d^4)