What is [4^{x^2}-3x+2]^{-2} ?

The solution to [4^{x^2}-3x+2]^{-2} is 1/((4^{x^2)-3x+2)^2}

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simplify [4^{x^2}-3x+2]^{-2}

simplify

[4^{x^{2}} - 3 x + 2]^{- 2}

\frac{1}{( 4 ^{x^{2}} - 3 x + 2 ) ^{2}}

Solution steps

(4^{x^{2}} - 3 x + 2)^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(4^{x^{2}} - 3 x + 2)^{- 2} = \frac{1}{( 4 ^{x^{2}} - 3 x + 2 ) ^{2}}

= \frac{1}{( 4 ^{x^{2}} - 3 x + 2 ) ^{2}}

\frac{6 z ^{0} + ( 5 m ) ^{0}}{21}

(- x \cdot y^{2}) \cdot (- x \cdot y)^{3}

(- x^{2} + x - 1)^{3} + x^{2} - x + 1

5 x^{10} \cdot y^{5} + 10 x^{8} \cdot y^{15} + 25 x^{16} \cdot y^{25}

9 m^{4} + 14 m^{2} \cdot n^{2} + 25 n^{4}

What is [4^{x^2}-3x+2]^{-2} ?
The solution to [4^{x^2}-3x+2]^{-2} is 1/((4^{x^2)-3x+2)^2}